merge *-all.* into *-recursive.*
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@@ -42,19 +42,44 @@ pushd $FONPATH
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echo "*** Starting from [`pwd`] ***"
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echo ""
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find . -mindepth 1 -maxdepth 3 -type d -name '[^.]*' | grep -E -v 'node_modules uni_modules .deploy_git .git .svn .vscode unpackage _webroot _logstore _datasotre _archive _filestore _ssl' | while read repo
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do
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if ( [ -f "$repo/package.json" ] && grep -q '"boot"' "$repo/package.json" )
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then
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if [ "$2" == 'hier' ]
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then
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# for org in `ls -F | grep '/$' | grep -v '~'` ## 首先过滤出所有子目录,然后过滤出所有不含 ~ 的子目录。注意 for ??? in `ls ???` 是按照空行以及空格进行分割的,因此最后筛选出的目录名不能含有空格,否则就被分割成多个了。
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ls -F | grep '/$' | grep -v '=' | while read org ## 换用这种方法,可以成功过滤出含有空格的完整目录名
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do
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echo "======== entering [$FONPATH/$org] ========"
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echo ""
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echo "---- npm booting: [$repo] ----"
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echo ""
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pushd "$repo"
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npm run boot
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echo ""
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echo "---- npm booted: [$repo] ----"
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echo ""
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popd
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fi
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done
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cd "$org";
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for repo in * ## for ??? in * 是分割成一个个目录名的,即使目录名含有空格
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do
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if ( [ -f "$repo/package.json" ] && grep -q '"boot"' "$repo/package.json" )
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then
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echo "<<<< npm booting: [$org/$repo] <<<<"
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cd "$repo"
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npm run boot
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echo ">>>> npm booted: [$org/$repo] >>>>"
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echo ""
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cd ..
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fi
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done
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cd ..;
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done
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else
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find . -mindepth 1 -maxdepth 3 -type d -name '[^.]*' | grep -E -v 'node_modules uni_modules .deploy_git .git .svn .vscode unpackage _webroot _logstore _datasotre _archive _filestore _ssl' | while read repo
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do
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if ( [ -f "$repo/package.json" ] && grep -q '"boot"' "$repo/package.json" )
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then
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echo ""
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echo "---- npm booting: [$repo] ----"
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echo ""
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pushd "$repo"
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npm run boot
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echo ""
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echo "---- npm booted: [$repo] ----"
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echo ""
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popd
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fi
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done
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fi
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popd
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