#!/bin/bash testpath1=/faronear testpath2=~/faronear testpath3=/mnt/d/faronear if [ "$1" ] then FONPATH=$1 elif [ -d $testpath1 ] then FONPATH=$testpath1 elif [ -d $testpath2 ] then FONPATH=$testpath2 elif [ -d $testpath3 ] then FONPATH=$testpath3 else echo "=== Enter [target path] or leave [blank] for default to '.'" read -p ">>> " FONPATH echo "" if [ ! "$FONPATH" ] then FONPATH=. fi fi if [ ! -d "$FONPATH" ] then echo "*** [$FONPATH] not exist! Exit now. ***" exit fi pushd $FONPATH echo "*** Starting from [`pwd`] ***" echo "" # for org in `ls -F | grep '/$' | grep -v '~'` ## 首先过滤出所有子目录,然后过滤出所有不含 ~ 的子目录。注意 for ??? in `ls ???` 是按照空行以及空格进行分割的,因此最后筛选出的目录名不能含有空格,否则就被分割成多个了。 ls -F | grep '/$' | grep -v '=' | while read org ## 换用这种方法,可以成功过滤出含有空格的完整目录名 do echo "======== entering [$FONPATH/$org] ========" echo "" cd "$org"; for repo in * ## for ??? in * 是分割成一个个目录名的,即使目录名含有空格 do if ( [ -f "$repo/package.json" ] && grep -q '"boot"' "$repo/package.json" ) then echo "<<<< npm booting: [$org/$repo] <<<<" cd "$repo" npm run boot echo ">>>> npm booted: [$org/$repo] >>>>" echo "" cd .. fi done cd ..; done popd